Base | Representation |
---|---|
bin | 1011101001111000001… |
… | …1000100111000000111 |
3 | 201010210200110000212221 |
4 | 2322132003010320013 |
5 | 11240022321232101 |
6 | 231551351353211 |
7 | 20315432534146 |
oct | 2723603047007 |
9 | 633720400787 |
10 | 200220102151 |
11 | 77a05034203 |
12 | 32979382807 |
13 | 15b5aac4234 |
14 | 999541775d |
15 | 531c94eaa1 |
hex | 2e9e0c4e07 |
200220102151 has 2 divisors, whose sum is σ = 200220102152. Its totient is φ = 200220102150.
The previous prime is 200220102133. The next prime is 200220102191. The reversal of 200220102151 is 151201022002.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200220102151 - 215 = 200220069383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200220102191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100110051075 + 100110051076.
It is an arithmetic number, because the mean of its divisors is an integer number (100110051076).
Almost surely, 2200220102151 is an apocalyptic number.
200220102151 is a deficient number, since it is larger than the sum of its proper divisors (1).
200220102151 is an equidigital number, since it uses as much as digits as its factorization.
200220102151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 16.
Adding to 200220102151 its reverse (151201022002), we get a palindrome (351421124153).
The spelling of 200220102151 in words is "two hundred billion, two hundred twenty million, one hundred two thousand, one hundred fifty-one".
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