Base | Representation |
---|---|
bin | 1001000110101101111001… |
… | …10111000100101000010011 |
3 | 2121220002022101021021002212 |
4 | 10203112330313010220103 |
5 | 10111020034321321042 |
6 | 110325552424502335 |
7 | 4134354046323551 |
oct | 443267467045023 |
9 | 77802271237085 |
10 | 20022011120147 |
11 | 641a318339423 |
12 | 22b449701a9ab |
13 | b230b552a39a |
14 | 4d30db694bd1 |
15 | 24ac4245e482 |
hex | 1235bcdc4a13 |
20022011120147 has 2 divisors, whose sum is σ = 20022011120148. Its totient is φ = 20022011120146.
The previous prime is 20022011120077. The next prime is 20022011120171. The reversal of 20022011120147 is 74102111022002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20022011120147 - 216 = 20022011054611 is a prime.
It is not a weakly prime, because it can be changed into another prime (20022011120647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10011005560073 + 10011005560074.
It is an arithmetic number, because the mean of its divisors is an integer number (10011005560074).
Almost surely, 220022011120147 is an apocalyptic number.
20022011120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20022011120147 is an equidigital number, since it uses as much as digits as its factorization.
20022011120147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 20022011120147 its reverse (74102111022002), we get a palindrome (94124122142149).
The spelling of 20022011120147 in words is "twenty trillion, twenty-two billion, eleven million, one hundred twenty thousand, one hundred forty-seven".
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