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2002202212111 = 113149118916803
BaseRepresentation
bin11101001000101100100…
…011010011011100001111
321002102000220200211001121
4131020230203103130033
5230301002231241421
64131444330021411
7264440302666363
oct35105443233417
97072026624047
102002202212111
11702146a513a2
12284059577867
13116a6488b86a
146cc9b1452a3
15371364d4d41
hex1d22c8d370f

2002202212111 has 8 divisors (see below), whose sum is σ = 2033477348400. Its totient is φ = 1971164909952.

The previous prime is 2002202212097. The next prime is 2002202212163. The reversal of 2002202212111 is 1112122022002.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2002202212111 - 213 = 2002202203919 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002202212411) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59441565 + ... + 59475238.

It is an arithmetic number, because the mean of its divisors is an integer number (254184668550).

Almost surely, 22002202212111 is an apocalyptic number.

2002202212111 is a deficient number, since it is larger than the sum of its proper divisors (31275136289).

2002202212111 is a wasteful number, since it uses less digits than its factorization.

2002202212111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118917065.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 2002202212111 its reverse (1112122022002), we get a palindrome (3114324234113).

The spelling of 2002202212111 in words is "two trillion, two billion, two hundred two million, two hundred twelve thousand, one hundred eleven".

Divisors: 1 113 149 16837 118916803 13437598739 17718603647 2002202212111