Base | Representation |
---|---|
bin | 1001000110101101111011… |
… | …00101100100111100000111 |
3 | 2121220002100020012121222001 |
4 | 10203112331211210330013 |
5 | 10111020100431423421 |
6 | 110325553542050131 |
7 | 4134354255046663 |
oct | 443267545447407 |
9 | 77802306177861 |
10 | 20022023311111 |
11 | 641a3242056a8 |
12 | 22b449b119947 |
13 | b230b7c08283 |
14 | 4d30dd1498a3 |
15 | 24ac4356b691 |
hex | 1235bd964f07 |
20022023311111 has 4 divisors (see below), whose sum is σ = 20892546063792. Its totient is φ = 19151500558432.
The previous prime is 20022023311097. The next prime is 20022023311117. The reversal of 20022023311111 is 11111332022002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20022023311111 - 25 = 20022023311079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20022023311117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435261376306 + ... + 435261376351.
It is an arithmetic number, because the mean of its divisors is an integer number (5223136515948).
Almost surely, 220022023311111 is an apocalyptic number.
20022023311111 is a deficient number, since it is larger than the sum of its proper divisors (870522752681).
20022023311111 is an equidigital number, since it uses as much as digits as its factorization.
20022023311111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 870522752680.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 20022023311111 its reverse (11111332022002), we get a palindrome (31133355333113).
The spelling of 20022023311111 in words is "twenty trillion, twenty-two billion, twenty-three million, three hundred eleven thousand, one hundred eleven".
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