Base | Representation |
---|---|
bin | 11101001000101101000… |
… | …101100101110001101111 |
3 | 21002102001112121110021111 |
4 | 131020231011211301233 |
5 | 230301012031400421 |
6 | 4131445250412451 |
7 | 264440442252433 |
oct | 35105505456157 |
9 | 7072045543244 |
10 | 2002211200111 |
11 | 7021510301a1 |
12 | 284060591127 |
13 | 116a666b78c5 |
14 | 6cc9c4049c3 |
15 | 371371acee1 |
hex | 1d22d165c6f |
2002211200111 has 2 divisors, whose sum is σ = 2002211200112. Its totient is φ = 2002211200110.
The previous prime is 2002211200069. The next prime is 2002211200117. The reversal of 2002211200111 is 1110021122002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2002211200111 - 211 = 2002211198063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2002211200091 and 2002211200100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2002211200117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001105600055 + 1001105600056.
It is an arithmetic number, because the mean of its divisors is an integer number (1001105600056).
Almost surely, 22002211200111 is an apocalyptic number.
2002211200111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002211200111 is an equidigital number, since it uses as much as digits as its factorization.
2002211200111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 2002211200111 its reverse (1110021122002), we get a palindrome (3112232322113).
The spelling of 2002211200111 in words is "two trillion, two billion, two hundred eleven million, two hundred thousand, one hundred eleven".
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