Base | Representation |
---|---|
bin | 101101100001100111010001… |
… | …001100010011101011011111 |
3 | 222020221000222102222201121112 |
4 | 231201213101030103223133 |
5 | 202220414124011231421 |
6 | 1545500414514052235 |
7 | 60113363546124101 |
oct | 5541472114235337 |
9 | 866830872881545 |
10 | 200222000102111 |
11 | 5888474530a919 |
12 | 1a55844687a07b |
13 | 8794b13467650 |
14 | 3762b218b1571 |
15 | 1823378b6245b |
hex | b619d1313adf |
200222000102111 has 4 divisors (see below), whose sum is σ = 215623692417672. Its totient is φ = 184820307786552.
The previous prime is 200222000102099. The next prime is 200222000102119. The reversal of 200222000102111 is 111201000222002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200222000102111 - 222 = 200221995907807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200222000102119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7700846157761 + ... + 7700846157786.
It is an arithmetic number, because the mean of its divisors is an integer number (53905923104418).
Almost surely, 2200222000102111 is an apocalyptic number.
200222000102111 is a deficient number, since it is larger than the sum of its proper divisors (15401692315561).
200222000102111 is a wasteful number, since it uses less digits than its factorization.
200222000102111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15401692315560.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 200222000102111 its reverse (111201000222002), we get a palindrome (311423000324113).
The spelling of 200222000102111 in words is "two hundred trillion, two hundred twenty-two billion, one hundred two thousand, one hundred eleven".
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