Base | Representation |
---|---|
bin | 1011101001111000111… |
… | …0100011100101000101 |
3 | 201010210220002220221001 |
4 | 2322132032203211011 |
5 | 11240024104031433 |
6 | 231551540053301 |
7 | 20315500236556 |
oct | 2723616434505 |
9 | 633726086831 |
10 | 200223111493 |
11 | 77a067aa169 |
12 | 3297a394231 |
13 | 15b5b608c02 |
14 | 999599c32d |
15 | 531cd4657d |
hex | 2e9e3a3945 |
200223111493 has 2 divisors, whose sum is σ = 200223111494. Its totient is φ = 200223111492.
The previous prime is 200223111469. The next prime is 200223111523. The reversal of 200223111493 is 394111322002.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 196680719169 + 3542392324 = 443487^2 + 59518^2 .
It is a cyclic number.
It is not a de Polignac number, because 200223111493 - 217 = 200222980421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200223121493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100111555746 + 100111555747.
It is an arithmetic number, because the mean of its divisors is an integer number (100111555747).
Almost surely, 2200223111493 is an apocalyptic number.
It is an amenable number.
200223111493 is a deficient number, since it is larger than the sum of its proper divisors (1).
200223111493 is an equidigital number, since it uses as much as digits as its factorization.
200223111493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 200223111493 its reverse (394111322002), we get a palindrome (594334433495).
The spelling of 200223111493 in words is "two hundred billion, two hundred twenty-three million, one hundred eleven thousand, four hundred ninety-three".
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