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20022425413 is a prime number
BaseRepresentation
bin10010101001011011…
…011111011101000101
31220200101201121010121
4102221123133131011
5312001220103123
613110450021541
71306113544054
oct225133373505
956611647117
1020022425413
118545156621
123a695778b1
131b7122a003
14d7d28239b
157c2bea75d
hex4a96df745

20022425413 has 2 divisors, whose sum is σ = 20022425414. Its totient is φ = 20022425412.

The previous prime is 20022425407. The next prime is 20022425419. The reversal of 20022425413 is 31452422002.

It is a balanced prime because it is at equal distance from previous prime (20022425407) and next prime (20022425419).

It can be written as a sum of positive squares in only one way, i.e., 13526387809 + 6496037604 = 116303^2 + 80598^2 .

It is a cyclic number.

It is not a de Polignac number, because 20022425413 - 233 = 11432490821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20022425419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10011212706 + 10011212707.

It is an arithmetic number, because the mean of its divisors is an integer number (10011212707).

Almost surely, 220022425413 is an apocalyptic number.

It is an amenable number.

20022425413 is a deficient number, since it is larger than the sum of its proper divisors (1).

20022425413 is an equidigital number, since it uses as much as digits as its factorization.

20022425413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 25.

Adding to 20022425413 its reverse (31452422002), we get a palindrome (51474847415).

The spelling of 20022425413 in words is "twenty billion, twenty-two million, four hundred twenty-five thousand, four hundred thirteen".