Base | Representation |
---|---|
bin | 11101001000110011001… |
… | …001111011010010110000 |
3 | 21002102022122011102121220 |
4 | 131020303021323102300 |
5 | 230301214112000422 |
6 | 4131503324345040 |
7 | 264443116452435 |
oct | 35106311732260 |
9 | 7072278142556 |
10 | 2002313000112 |
11 | 7021a3541027 |
12 | 28408a6a5180 |
13 | 116a8180b7a9 |
14 | 6ccabb43b8c |
15 | 371410bae5c |
hex | 1d23327b4b0 |
2002313000112 has 40 divisors (see below), whose sum is σ = 5172811270080. Its totient is φ = 667415814720.
The previous prime is 2002313000099. The next prime is 2002313000147. The reversal of 2002313000112 is 2110003132002.
It is a super-2 number, since 2×20023130001122 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2002313000091 and 2002313000100.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 833187 + ... + 2167677.
It is an arithmetic number, because the mean of its divisors is an integer number (129320281752).
Almost surely, 22002313000112 is an apocalyptic number.
It is an amenable number.
2002313000112 is an abundant number, since it is smaller than the sum of its proper divisors (3170498269968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2002313000112 is a wasteful number, since it uses less digits than its factorization.
2002313000112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1365761 (or 1365755 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 2002313000112 its reverse (2110003132002), we get a palindrome (4112316132114).
The spelling of 2002313000112 in words is "two trillion, two billion, three hundred thirteen million, one hundred twelve", and thus it is an aban number.
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