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20023134333 = 36674378111
BaseRepresentation
bin10010101001011110…
…001100100001111101
31220200110001121120220
4102221132030201331
5312001410244313
613110513131553
71306122555636
oct225136144175
956613047526
1020023134333
1185455a0204
123a69859bb9
131b714178a7
14d7d3c888d
157c2cda823
hex4a978c87d

20023134333 has 4 divisors (see below), whose sum is σ = 26697512448. Its totient is φ = 13348756220.

The previous prime is 20023134323. The next prime is 20023134337. The reversal of 20023134333 is 33343132002.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20023134333 - 25 = 20023134301 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20023134337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3337189053 + ... + 3337189058.

It is an arithmetic number, because the mean of its divisors is an integer number (6674378112).

Almost surely, 220023134333 is an apocalyptic number.

It is an amenable number.

20023134333 is a deficient number, since it is larger than the sum of its proper divisors (6674378115).

20023134333 is an equidigital number, since it uses as much as digits as its factorization.

20023134333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6674378114.

The product of its (nonzero) digits is 3888, while the sum is 24.

Adding to 20023134333 its reverse (33343132002), we get a palindrome (53366266335).

The spelling of 20023134333 in words is "twenty billion, twenty-three million, one hundred thirty-four thousand, three hundred thirty-three".

Divisors: 1 3 6674378111 20023134333