Base | Representation |
---|---|
bin | 1001000110110000010011… |
… | …01100111100111111001011 |
3 | 2121220012122020010001021121 |
4 | 10203120021230330333023 |
5 | 10111030204340004120 |
6 | 110330324400420111 |
7 | 4134431022303445 |
oct | 443301154747713 |
9 | 77805566101247 |
10 | 20023300313035 |
11 | 641a91a025098 |
12 | 22b4796917637 |
13 | b2325c650306 |
14 | 4d31c09a1495 |
15 | 24acba7175aa |
hex | 123609b3cfcb |
20023300313035 has 8 divisors (see below), whose sum is σ = 24037453856016. Its totient is φ = 16012311263520.
The previous prime is 20023300312987. The next prime is 20023300313077. The reversal of 20023300313035 is 53031300332002.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20023300313035 - 29 = 20023300312523 is a prime.
It is a super-2 number, since 2×200233003130352 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 791109444 + ... + 791134753.
It is an arithmetic number, because the mean of its divisors is an integer number (3004681732002).
Almost surely, 220023300313035 is an apocalyptic number.
20023300313035 is a deficient number, since it is larger than the sum of its proper divisors (4014153542981).
20023300313035 is a wasteful number, since it uses less digits than its factorization.
20023300313035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1582246733.
The product of its (nonzero) digits is 4860, while the sum is 25.
Adding to 20023300313035 its reverse (53031300332002), we get a palindrome (73054600645037).
The spelling of 20023300313035 in words is "twenty trillion, twenty-three billion, three hundred million, three hundred thirteen thousand, thirty-five".
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