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20023300313035 = 525311582244197
BaseRepresentation
bin1001000110110000010011…
…01100111100111111001011
32121220012122020010001021121
410203120021230330333023
510111030204340004120
6110330324400420111
74134431022303445
oct443301154747713
977805566101247
1020023300313035
11641a91a025098
1222b4796917637
13b2325c650306
144d31c09a1495
1524acba7175aa
hex123609b3cfcb

20023300313035 has 8 divisors (see below), whose sum is σ = 24037453856016. Its totient is φ = 16012311263520.

The previous prime is 20023300312987. The next prime is 20023300313077. The reversal of 20023300313035 is 53031300332002.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20023300313035 - 29 = 20023300312523 is a prime.

It is a super-2 number, since 2×200233003130352 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 791109444 + ... + 791134753.

It is an arithmetic number, because the mean of its divisors is an integer number (3004681732002).

Almost surely, 220023300313035 is an apocalyptic number.

20023300313035 is a deficient number, since it is larger than the sum of its proper divisors (4014153542981).

20023300313035 is a wasteful number, since it uses less digits than its factorization.

20023300313035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1582246733.

The product of its (nonzero) digits is 4860, while the sum is 25.

Adding to 20023300313035 its reverse (53031300332002), we get a palindrome (73054600645037).

The spelling of 20023300313035 in words is "twenty trillion, twenty-three billion, three hundred million, three hundred thirteen thousand, thirty-five".

Divisors: 1 5 2531 12655 1582244197 7911220985 4004660062607 20023300313035