Base | Representation |
---|---|
bin | 1001000110110000010011… |
… | …11011100110110010011111 |
3 | 2121220012122111100012110121 |
4 | 10203120021323212302133 |
5 | 10111030211330414041 |
6 | 110330325015015411 |
7 | 4134431100042415 |
oct | 443301173466237 |
9 | 77805574305417 |
10 | 20023304154271 |
11 | 641a921209070 |
12 | 22b479806a567 |
13 | b23260396832 |
14 | 4d31c12c12b5 |
15 | 24acbac257d1 |
hex | 123609ee6c9f |
20023304154271 has 4 divisors (see below), whose sum is σ = 21843604531944. Its totient is φ = 18203003776600.
The previous prime is 20023304154253. The next prime is 20023304154299. The reversal of 20023304154271 is 17245140332002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20023304154271 - 215 = 20023304121503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20023304154221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 910150188820 + ... + 910150188841.
It is an arithmetic number, because the mean of its divisors is an integer number (5460901132986).
Almost surely, 220023304154271 is an apocalyptic number.
20023304154271 is a deficient number, since it is larger than the sum of its proper divisors (1820300377673).
20023304154271 is a wasteful number, since it uses less digits than its factorization.
20023304154271 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1820300377672.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 20023304154271 its reverse (17245140332002), we get a palindrome (37268444486273).
The spelling of 20023304154271 in words is "twenty trillion, twenty-three billion, three hundred four million, one hundred fifty-four thousand, two hundred seventy-one".
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