Base | Representation |
---|---|
bin | 1011101001111101000… |
… | …0101010101100100111 |
3 | 201010212002201102010021 |
4 | 2322133100222230213 |
5 | 11240043023122101 |
6 | 231553355340011 |
7 | 20316100450351 |
oct | 2723720525447 |
9 | 633762642107 |
10 | 200240442151 |
11 | 77a15566a22 |
12 | 32984151607 |
13 | 15b62096339 |
14 | 9997dd00d1 |
15 | 531e61b5a1 |
hex | 2e9f42ab27 |
200240442151 has 2 divisors, whose sum is σ = 200240442152. Its totient is φ = 200240442150.
The previous prime is 200240442091. The next prime is 200240442211. The reversal of 200240442151 is 151244042002.
It is a balanced prime because it is at equal distance from previous prime (200240442091) and next prime (200240442211).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200240442151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200240442251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100120221075 + 100120221076.
It is an arithmetic number, because the mean of its divisors is an integer number (100120221076).
Almost surely, 2200240442151 is an apocalyptic number.
200240442151 is a deficient number, since it is larger than the sum of its proper divisors (1).
200240442151 is an equidigital number, since it uses as much as digits as its factorization.
200240442151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2560, while the sum is 25.
Adding to 200240442151 its reverse (151244042002), we get a palindrome (351484484153).
The spelling of 200240442151 in words is "two hundred billion, two hundred forty million, four hundred forty-two thousand, one hundred fifty-one".
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