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200241000301303 = 1315403153869331
BaseRepresentation
bin101101100001111000111101…
…101100010100001011110111
3222020222212000121012211222201
4231201320331230110023313
5202221222032034120203
61545513240130205331
760114635441136613
oct5541707554241367
9866885017184881
10200241000301303
1158891805441785
121a560069a23847
138796850974970
143763a0509c343
151823adbc3ae1d
hexb61e3db142f7

200241000301303 has 4 divisors (see below), whose sum is σ = 215644154170648. Its totient is φ = 184837846431960.

The previous prime is 200241000301259. The next prime is 200241000301337. The reversal of 200241000301303 is 303103000142002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200241000301303 - 225 = 200240966746871 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200241000301343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7701576934653 + ... + 7701576934678.

It is an arithmetic number, because the mean of its divisors is an integer number (53911038542662).

Almost surely, 2200241000301303 is an apocalyptic number.

200241000301303 is a deficient number, since it is larger than the sum of its proper divisors (15403153869345).

200241000301303 is a wasteful number, since it uses less digits than its factorization.

200241000301303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15403153869344.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 200241000301303 its reverse (303103000142002), we get a palindrome (503344000443305).

The spelling of 200241000301303 in words is "two hundred trillion, two hundred forty-one billion, three hundred one thousand, three hundred three".

Divisors: 1 13 15403153869331 200241000301303