Search a number
-
+
2002411034143 = 13374163016703
BaseRepresentation
bin11101001000111000111…
…111111001011000011111
321002102120110122002000221
4131020320333321120133
5230301414211043033
64131521145502211
7264445416646102
oct35107077713037
97072513562027
102002411034143
1170224390a493
122840b74a1967
13116a98c144b0
146ccbab82739
15371499d312d
hex1d238ff961f

2002411034143 has 8 divisors (see below), whose sum is σ = 2214724886528. Its totient is φ = 1798423215264.

The previous prime is 2002411034119. The next prime is 2002411034149. The reversal of 2002411034143 is 3414301142002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-2002411034143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002411034149) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2081507871 + ... + 2081508832.

It is an arithmetic number, because the mean of its divisors is an integer number (276840610816).

Almost surely, 22002411034143 is an apocalyptic number.

2002411034143 is a deficient number, since it is larger than the sum of its proper divisors (212313852385).

2002411034143 is a wasteful number, since it uses less digits than its factorization.

2002411034143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4163016753.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 2002411034143 its reverse (3414301142002), we get a palindrome (5416712176145).

The spelling of 2002411034143 in words is "two trillion, two billion, four hundred eleven million, thirty-four thousand, one hundred forty-three".

Divisors: 1 13 37 481 4163016703 54119217139 154031618011 2002411034143