Base | Representation |
---|---|
bin | 1011101001111101011… |
… | …1011000001001110011 |
3 | 201010212020000210002100 |
4 | 2322133113120021303 |
5 | 11240044000414303 |
6 | 231553501151443 |
7 | 20316121424652 |
oct | 2723727301163 |
9 | 633766023070 |
10 | 200242201203 |
11 | 77a16558590 |
12 | 3298485b583 |
13 | 15b62560bb5 |
14 | 999832b199 |
15 | 531e8678a3 |
hex | 2e9f5d8273 |
200242201203 has 96 divisors (see below), whose sum is σ = 337934757888. Its totient is φ = 113061009600.
The previous prime is 200242201169. The next prime is 200242201219. The reversal of 200242201203 is 302102242002.
200242201203 is a `hidden beast` number, since 20 + 0 + 242 + 201 + 203 = 666.
It is not a de Polignac number, because 200242201203 - 217 = 200242070131 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200242201603) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 13410900 + ... + 13425822.
It is an arithmetic number, because the mean of its divisors is an integer number (3520153728).
Almost surely, 2200242201203 is an apocalyptic number.
200242201203 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
200242201203 is a deficient number, since it is larger than the sum of its proper divisors (137692556685).
200242201203 is a wasteful number, since it uses less digits than its factorization.
200242201203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15117 (or 15114 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 18.
Adding to 200242201203 its reverse (302102242002), we get a palindrome (502344443205).
The spelling of 200242201203 in words is "two hundred billion, two hundred forty-two million, two hundred one thousand, two hundred three".
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