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2002433041011 = 313217232327769
BaseRepresentation
bin11101001000111010010…
…011110110001001110011
321002102122000001010210010
4131020322103312021303
5230301440324303021
64131523253310003
7264446105004054
oct35107223661163
97072560033703
102002433041011
11702255280587
12284102935303
13116aa064b200
146ccbda7072b
153714b8cd976
hex1d23a4f6273

2002433041011 has 24 divisors (see below), whose sum is σ = 3061150697520. Its totient is φ = 1159780217856.

The previous prime is 2002433041009. The next prime is 2002433041067. The reversal of 2002433041011 is 1101403342002.

It is not a de Polignac number, because 2002433041011 - 21 = 2002433041009 is a prime.

It is a super-2 number, since 2×20024330410112 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2002433041811) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 116155266 + ... + 116172503.

It is an arithmetic number, because the mean of its divisors is an integer number (127547945730).

Almost surely, 22002433041011 is an apocalyptic number.

2002433041011 is a deficient number, since it is larger than the sum of its proper divisors (1058717656509).

2002433041011 is a wasteful number, since it uses less digits than its factorization.

2002433041011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 232327815 (or 232327802 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 2002433041011 its reverse (1101403342002), we get a palindrome (3103836383013).

The spelling of 2002433041011 in words is "two trillion, two billion, four hundred thirty-three million, forty-one thousand, eleven".

Divisors: 1 3 13 17 39 51 169 221 507 663 2873 8619 232327769 696983307 3020260997 3949572073 9060782991 11848716219 39263392961 51344436949 117790178883 154033310847 667477680337 2002433041011