Base | Representation |
---|---|
bin | 10010101001100010… |
… | …110001011111111111 |
3 | 1220200112022120200102 |
4 | 102221202301133333 |
5 | 312002212144320 |
6 | 13110554551315 |
7 | 1306136014325 |
oct | 225142613777 |
9 | 56615276612 |
10 | 20024334335 |
11 | 854623a845 |
12 | 3a6a13853b |
13 | 1b71747b55 |
14 | d7d61bd15 |
15 | 7c2e76175 |
hex | 4a98b17ff |
20024334335 has 4 divisors (see below), whose sum is σ = 24029201208. Its totient is φ = 16019467464.
The previous prime is 20024334331. The next prime is 20024334361. The reversal of 20024334335 is 53343342002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20024334335 - 22 = 20024334331 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20024334298 and 20024334307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20024334331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002433429 + ... + 2002433438.
It is an arithmetic number, because the mean of its divisors is an integer number (6007300302).
Almost surely, 220024334335 is an apocalyptic number.
20024334335 is a deficient number, since it is larger than the sum of its proper divisors (4004866873).
20024334335 is an equidigital number, since it uses as much as digits as its factorization.
20024334335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4004866872.
The product of its (nonzero) digits is 25920, while the sum is 29.
Adding to 20024334335 its reverse (53343342002), we get a palindrome (73367676337).
The spelling of 20024334335 in words is "twenty billion, twenty-four million, three hundred thirty-four thousand, three hundred thirty-five".
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