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20025435435133 is a prime number
BaseRepresentation
bin1001000110110100010001…
…11101110011000001111101
32121220102011000201111011211
410203122020331303001331
510111044042432411013
6110331320311444421
74134534646451302
oct443321075630175
977812130644154
1020025435435133
116420815271a07
1222b5091986711
13b2350cab767b
144d33443910a9
1524ad92dbb23d
hex123688f7307d

20025435435133 has 2 divisors, whose sum is σ = 20025435435134. Its totient is φ = 20025435435132.

The previous prime is 20025435435119. The next prime is 20025435435139. The reversal of 20025435435133 is 33153453452002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16828069453209 + 3197365981924 = 4102203^2 + 1788118^2 .

It is a cyclic number.

It is not a de Polignac number, because 20025435435133 - 29 = 20025435434621 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20025435435139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10012717717566 + 10012717717567.

It is an arithmetic number, because the mean of its divisors is an integer number (10012717717567).

Almost surely, 220025435435133 is an apocalyptic number.

It is an amenable number.

20025435435133 is a deficient number, since it is larger than the sum of its proper divisors (1).

20025435435133 is an equidigital number, since it uses as much as digits as its factorization.

20025435435133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648000, while the sum is 40.

Adding to 20025435435133 its reverse (33153453452002), we get a palindrome (53178888887135).

The spelling of 20025435435133 in words is "twenty trillion, twenty-five billion, four hundred thirty-five million, four hundred thirty-five thousand, one hundred thirty-three".