Base | Representation |
---|---|
bin | 11101001001011100110… |
… | …000101101001111001101 |
3 | 21002111010021122010101021 |
4 | 131021130300231033031 |
5 | 230304131311011023 |
6 | 4132100501514141 |
7 | 264466323566035 |
oct | 35113460551715 |
9 | 7074107563337 |
10 | 2003011032013 |
11 | 7025215667a2 |
12 | 284244412951 |
13 | 116b6330c114 |
14 | 6cd367288c5 |
15 | 3718250035d |
hex | 1d25cc2d3cd |
2003011032013 has 4 divisors (see below), whose sum is σ = 2008160161020. Its totient is φ = 1997861903008.
The previous prime is 2003011031977. The next prime is 2003011032019. The reversal of 2003011032013 is 3102301103002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 149674586884 + 1853336445129 = 386878^2 + 1361373^2 .
It is a cyclic number.
It is not a de Polignac number, because 2003011032013 - 217 = 2003010900941 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2003011032019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2574563920 + ... + 2574564697.
It is an arithmetic number, because the mean of its divisors is an integer number (502040040255).
Almost surely, 22003011032013 is an apocalyptic number.
It is an amenable number.
2003011032013 is a deficient number, since it is larger than the sum of its proper divisors (5149129007).
2003011032013 is an equidigital number, since it uses as much as digits as its factorization.
2003011032013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5149129006.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 2003011032013 its reverse (3102301103002), we get a palindrome (5105312135015).
The spelling of 2003011032013 in words is "two trillion, three billion, eleven million, thirty-two thousand, thirteen".
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