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2003031311111 = 41111148942409
BaseRepresentation
bin11101001001011101111…
…110000100001100000111
321002111011200210102001222
4131021131332010030013
5230304202003423421
64132102504310555
7264466661136545
oct35113576041407
97074150712058
102003031311111
11702531a57786
1228424b17245b
13116b6758c59c
146cd392c6d95
15371841a8cab
hex1d25df84307

2003031311111 has 8 divisors (see below), whose sum is σ = 2003740180800. Its totient is φ = 2002322557440.

The previous prime is 2003031311093. The next prime is 2003031311189. The reversal of 2003031311111 is 1111131303002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2003031311111 - 210 = 2003031310087 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2003031311111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003031319111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47210075 + ... + 47252483.

It is an arithmetic number, because the mean of its divisors is an integer number (250467522600).

Almost surely, 22003031311111 is an apocalyptic number.

2003031311111 is a deficient number, since it is larger than the sum of its proper divisors (708869689).

2003031311111 is a wasteful number, since it uses less digits than its factorization.

2003031311111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58009.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 2003031311111 its reverse (1111131303002), we get a palindrome (3114162614113).

The spelling of 2003031311111 in words is "two trillion, three billion, thirty-one million, three hundred eleven thousand, one hundred eleven".

Divisors: 1 4111 11489 42409 47231279 174343399 487237001 2003031311111