Base | Representation |
---|---|
bin | 10010101001111001… |
… | …101010010100101101 |
3 | 1220200221121102000121 |
4 | 102221321222110231 |
5 | 312010231144003 |
6 | 13111331324541 |
7 | 1306241013646 |
oct | 225171522455 |
9 | 56627542017 |
10 | 20030334253 |
11 | 8549668656 |
12 | 3a70150751 |
13 | 1b72a68ab7 |
14 | d803406cd |
15 | 7c375dcbd |
hex | 4a9e6a52d |
20030334253 has 2 divisors, whose sum is σ = 20030334254. Its totient is φ = 20030334252.
The previous prime is 20030334251. The next prime is 20030334263. The reversal of 20030334253 is 35243303002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20028476484 + 1857769 = 141522^2 + 1363^2 .
It is a cyclic number.
It is not a de Polignac number, because 20030334253 - 21 = 20030334251 is a prime.
Together with 20030334251, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20030334251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10015167126 + 10015167127.
It is an arithmetic number, because the mean of its divisors is an integer number (10015167127).
Almost surely, 220030334253 is an apocalyptic number.
It is an amenable number.
20030334253 is a deficient number, since it is larger than the sum of its proper divisors (1).
20030334253 is an equidigital number, since it uses as much as digits as its factorization.
20030334253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 25.
Adding to 20030334253 its reverse (35243303002), we get a palindrome (55273637255).
The spelling of 20030334253 in words is "twenty billion, thirty million, three hundred thirty-four thousand, two hundred fifty-three".
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