Base | Representation |
---|---|
bin | 1001000110111110101001… |
… | …10100110111100010101111 |
3 | 2121220221112001022200201222 |
4 | 10203133110310313202233 |
5 | 10111141443300130111 |
6 | 110334041002453555 |
7 | 4135122634206035 |
oct | 443372464674257 |
9 | 77827461280658 |
10 | 20031003130031 |
11 | 6423112072553 |
12 | 22b61865042bb |
13 | b23bb94408aa |
14 | 4d37119ca555 |
15 | 24b0bbaad7db |
hex | 1237d4d378af |
20031003130031 has 2 divisors, whose sum is σ = 20031003130032. Its totient is φ = 20031003130030.
The previous prime is 20031003130007. The next prime is 20031003130049. The reversal of 20031003130031 is 13003130013002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20031003130031 is a prime.
It is a super-2 number, since 2×200310031300312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20031003129991 and 20031003130009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20031003130051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10015501565015 + 10015501565016.
It is an arithmetic number, because the mean of its divisors is an integer number (10015501565016).
Almost surely, 220031003130031 is an apocalyptic number.
20031003130031 is a deficient number, since it is larger than the sum of its proper divisors (1).
20031003130031 is an equidigital number, since it uses as much as digits as its factorization.
20031003130031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 20031003130031 its reverse (13003130013002), we get a palindrome (33034133143033).
The spelling of 20031003130031 in words is "twenty trillion, thirty-one billion, three million, one hundred thirty thousand, thirty-one".
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