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20031004443095 = 54006200888619
BaseRepresentation
bin1001000110111110101001…
…11001111000000111010111
32121220221112010210101220222
410203133110321320013113
510111141444114134340
6110334041050544555
74135122651315152
oct443372471700727
977827463711828
1020031004443095
11642311288a028
1222b6186a3815b
13b23bb97b0459
144d3711c4cc99
1524b0bbc6c8b5
hex1237d4e781d7

20031004443095 has 4 divisors (see below), whose sum is σ = 24037205331720. Its totient is φ = 16024803554472.

The previous prime is 20031004443071. The next prime is 20031004443101. The reversal of 20031004443095 is 59034440013002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20031004443095 is a prime.

It is a super-2 number, since 2×200310044430952 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2003100444305 + ... + 2003100444314.

It is an arithmetic number, because the mean of its divisors is an integer number (6009301332930).

Almost surely, 220031004443095 is an apocalyptic number.

20031004443095 is a deficient number, since it is larger than the sum of its proper divisors (4006200888625).

20031004443095 is an equidigital number, since it uses as much as digits as its factorization.

20031004443095 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4006200888624.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 20031004443095 its reverse (59034440013002), we get a palindrome (79065444456097).

The spelling of 20031004443095 in words is "twenty trillion, thirty-one billion, four million, four hundred forty-three thousand, ninety-five".

Divisors: 1 5 4006200888619 20031004443095