Base | Representation |
---|---|
bin | 11101001001100010000… |
… | …101110010011010010111 |
3 | 21002111100111212201222212 |
4 | 131021202011302122113 |
5 | 230304322203204221 |
6 | 4132113414144035 |
7 | 264501460563221 |
oct | 35114205623227 |
9 | 7074314781885 |
10 | 2003100444311 |
11 | 702567a8655a |
12 | 28426a35201b |
13 | 116b789b66c5 |
14 | 6cd44561411 |
15 | 3718a2b2b5b |
hex | 1d262172697 |
2003100444311 has 2 divisors, whose sum is σ = 2003100444312. Its totient is φ = 2003100444310.
The previous prime is 2003100444299. The next prime is 2003100444329. The reversal of 2003100444311 is 1134440013002.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2003100444311 is a prime.
It is a super-2 number, since 2×20031004443112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003100444361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001550222155 + 1001550222156.
It is an arithmetic number, because the mean of its divisors is an integer number (1001550222156).
Almost surely, 22003100444311 is an apocalyptic number.
2003100444311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003100444311 is an equidigital number, since it uses as much as digits as its factorization.
2003100444311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 2003100444311 its reverse (1134440013002), we get a palindrome (3137540457313).
The spelling of 2003100444311 in words is "two trillion, three billion, one hundred million, four hundred forty-four thousand, three hundred eleven".
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