Base | Representation |
---|---|
bin | 1001000110111110101001… |
… | …11001111000001000000110 |
3 | 2121220221112010210101222201 |
4 | 10203133110321320020012 |
5 | 10111141444114140032 |
6 | 110334041050545114 |
7 | 4135122651315250 |
oct | 443372471701006 |
9 | 77827463711881 |
10 | 20031004443142 |
11 | 642311288a070 |
12 | 22b6186a3819a |
13 | b23bb97b0494 |
14 | 4d3711c4ccd0 |
15 | 24b0bbc6c8e7 |
hex | 1237d4e78206 |
20031004443142 has 48 divisors (see below), whose sum is σ = 37483865872128. Its totient is φ = 7799439175920.
The previous prime is 20031004443137. The next prime is 20031004443161. The reversal of 20031004443142 is 24134440013002.
It is a super-2 number, since 2×200310044431422 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20031004443142.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 427925503 + ... + 427972309.
It is an arithmetic number, because the mean of its divisors is an integer number (780913872336).
Almost surely, 220031004443142 is an apocalyptic number.
20031004443142 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
20031004443142 is a deficient number, since it is larger than the sum of its proper divisors (17452861428986).
20031004443142 is an equidigital number, since it uses as much as digits as its factorization.
20031004443142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50161 (or 48494 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 20031004443142 its reverse (24134440013002), we get a palindrome (44165444456144).
The spelling of 20031004443142 in words is "twenty trillion, thirty-one billion, four million, four hundred forty-three thousand, one hundred forty-two".
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