Base | Representation |
---|---|
bin | 101101100010111010001100… |
… | …011001011100001111000101 |
3 | 222021020112210210200220012120 |
4 | 231202322030121130033011 |
5 | 202223344002244332331 |
6 | 1550005342125040153 |
7 | 60122665211540505 |
oct | 5542721431341705 |
9 | 867215723626176 |
10 | 200311040230341 |
11 | 58909487126057 |
12 | 1a5717560b6059 |
13 | 87a033345c761 |
14 | 376716b109a05 |
15 | 182583aad7796 |
hex | b62e8c65c3c5 |
200311040230341 has 4 divisors (see below), whose sum is σ = 267081386973792. Its totient is φ = 133540693486892.
The previous prime is 200311040230337. The next prime is 200311040230349. The reversal of 200311040230341 is 143032040113002.
It is a happy number.
200311040230341 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 200311040230341 - 22 = 200311040230337 is a prime.
It is a super-2 number, since 2×2003110402303412 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200311040230349) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33385173371721 + ... + 33385173371726.
It is an arithmetic number, because the mean of its divisors is an integer number (66770346743448).
Almost surely, 2200311040230341 is an apocalyptic number.
It is an amenable number.
200311040230341 is a deficient number, since it is larger than the sum of its proper divisors (66770346743451).
200311040230341 is an equidigital number, since it uses as much as digits as its factorization.
200311040230341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66770346743450.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 200311040230341 its reverse (143032040113002), we get a palindrome (343343080343343).
The spelling of 200311040230341 in words is "two hundred trillion, three hundred eleven billion, forty million, two hundred thirty thousand, three hundred forty-one".
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