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2003112133 = 11182101103
BaseRepresentation
bin111011101100101…
…0001000011000101
312011121012122021021
41313121101003011
513100244042013
6530433351141
7100432113031
oct16731210305
95147178237
102003112133
11938782880
1247aa084b1
1325bcc6a69
141500691c1
15bacc9a8d
hex776510c5

2003112133 has 4 divisors (see below), whose sum is σ = 2185213248. Its totient is φ = 1821011020.

The previous prime is 2003112119. The next prime is 2003112149. The reversal of 2003112133 is 3312113002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2003112133 - 25 = 2003112101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003112233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91050541 + ... + 91050562.

It is an arithmetic number, because the mean of its divisors is an integer number (546303312).

Almost surely, 22003112133 is an apocalyptic number.

It is an amenable number.

2003112133 is a deficient number, since it is larger than the sum of its proper divisors (182101115).

2003112133 is a wasteful number, since it uses less digits than its factorization.

2003112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 182101114.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 2003112133 is about 44756.1407295133. The cubic root of 2003112133 is about 1260.5742182003.

Adding to 2003112133 its reverse (3312113002), we get a palindrome (5315225135).

The spelling of 2003112133 in words is "two billion, three million, one hundred twelve thousand, one hundred thirty-three".

Divisors: 1 11 182101103 2003112133