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2003112201317 is a prime number
BaseRepresentation
bin11101001001100010110…
…010101000110001100101
321002111101100000001120112
4131021202302220301211
5230304333210420232
64132114514142405
7264501662531213
oct35114262506145
97074340001515
102003112201317
11702573686797
12284272281a05
13116b7b271c06
146cd45d41cb3
153718b3364b2
hex1d262ca8c65

2003112201317 has 2 divisors, whose sum is σ = 2003112201318. Its totient is φ = 2003112201316.

The previous prime is 2003112201289. The next prime is 2003112201323. The reversal of 2003112201317 is 7131022113002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1467523879396 + 535588321921 = 1211414^2 + 731839^2 .

It is a cyclic number.

It is not a de Polignac number, because 2003112201317 - 26 = 2003112201253 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2003112201292 and 2003112201301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2003112201917) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001556100658 + 1001556100659.

It is an arithmetic number, because the mean of its divisors is an integer number (1001556100659).

Almost surely, 22003112201317 is an apocalyptic number.

It is an amenable number.

2003112201317 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003112201317 is an equidigital number, since it uses as much as digits as its factorization.

2003112201317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 2003112201317 its reverse (7131022113002), we get a palindrome (9134134314319).

The spelling of 2003112201317 in words is "two trillion, three billion, one hundred twelve million, two hundred one thousand, three hundred seventeen".