Base | Representation |
---|---|
bin | 11101001001100010110… |
… | …110100100101101001111 |
3 | 21002111101101221111002120 |
4 | 131021202312210231033 |
5 | 230304333441430411 |
6 | 4132114552224023 |
7 | 264502004356545 |
oct | 35114266445517 |
9 | 7074341844076 |
10 | 2003113233231 |
11 | 702574221010 |
12 | 28427269b013 |
13 | 116b7b543806 |
14 | 6cd4612dd95 |
15 | 3718b48c106 |
hex | 1d262da4b4f |
2003113233231 has 8 divisors (see below), whose sum is σ = 2913619248384. Its totient is φ = 1214008020120.
The previous prime is 2003113233221. The next prime is 2003113233347. The reversal of 2003113233231 is 1323323113002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2003113233231 - 211 = 2003113231183 is a prime.
It is a super-2 number, since 2×20031132332312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2003113233221) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30350200471 + ... + 30350200536.
It is an arithmetic number, because the mean of its divisors is an integer number (364202406048).
Almost surely, 22003113233231 is an apocalyptic number.
2003113233231 is a deficient number, since it is larger than the sum of its proper divisors (910506015153).
2003113233231 is a wasteful number, since it uses less digits than its factorization.
2003113233231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60700401021.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 2003113233231 its reverse (1323323113002), we get a palindrome (3326436346233).
The spelling of 2003113233231 in words is "two trillion, three billion, one hundred thirteen million, two hundred thirty-three thousand, two hundred thirty-one".
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