Base | Representation |
---|---|
bin | 11101001001100011010… |
… | …100001100111100010011 |
3 | 21002111101221120002101111 |
4 | 131021203110030330103 |
5 | 230304342434001321 |
6 | 4132115430514151 |
7 | 264502130366032 |
oct | 35114324147423 |
9 | 7074357502344 |
10 | 2003121000211 |
11 | 702578646501 |
12 | 284275205957 |
13 | 116b80032b66 |
14 | 6cd47192719 |
15 | 3718bec35e1 |
hex | 1d26350cf13 |
2003121000211 has 2 divisors, whose sum is σ = 2003121000212. Its totient is φ = 2003121000210.
The previous prime is 2003121000193. The next prime is 2003121000271. The reversal of 2003121000211 is 1120001213002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2003121000211 - 215 = 2003120967443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2003121000191 and 2003121000200.
It is not a weakly prime, because it can be changed into another prime (2003121000271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001560500105 + 1001560500106.
It is an arithmetic number, because the mean of its divisors is an integer number (1001560500106).
Almost surely, 22003121000211 is an apocalyptic number.
2003121000211 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003121000211 is an equidigital number, since it uses as much as digits as its factorization.
2003121000211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 2003121000211 its reverse (1120001213002), we get a palindrome (3123122213213).
The spelling of 2003121000211 in words is "two trillion, three billion, one hundred twenty-one million, two hundred eleven", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •