Base | Representation |
---|---|
bin | 11101001001100011010… |
… | …100001100111101001111 |
3 | 21002111101221120002110201 |
4 | 131021203110030331033 |
5 | 230304342434002041 |
6 | 4132115430514331 |
7 | 264502130366146 |
oct | 35114324147517 |
9 | 7074357502421 |
10 | 2003121000271 |
11 | 702578646556 |
12 | 2842752059a7 |
13 | 116b80032bb1 |
14 | 6cd4719275d |
15 | 3718bec3631 |
hex | 1d26350cf4f |
2003121000271 has 2 divisors, whose sum is σ = 2003121000272. Its totient is φ = 2003121000270.
The previous prime is 2003121000211. The next prime is 2003121000301. The reversal of 2003121000271 is 1720001213002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2003121000271 - 221 = 2003118903119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003121000211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001560500135 + 1001560500136.
It is an arithmetic number, because the mean of its divisors is an integer number (1001560500136).
Almost surely, 22003121000271 is an apocalyptic number.
2003121000271 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003121000271 is an equidigital number, since it uses as much as digits as its factorization.
2003121000271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 19.
Adding to 2003121000271 its reverse (1720001213002), we get a palindrome (3723122213273).
The spelling of 2003121000271 in words is "two trillion, three billion, one hundred twenty-one million, two hundred seventy-one", and thus it is an aban number.
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