Base | Representation |
---|---|
bin | 101101100010111011001100… |
… | …001010110010100000001011 |
3 | 222021020122120100220111021201 |
4 | 231202323030022302200023 |
5 | 202223403200143144321 |
6 | 1550010040224445031 |
7 | 60123033552543151 |
oct | 5542731412624013 |
9 | 867218510814251 |
10 | 200312110131211 |
11 | 58909986052451 |
12 | 1a5719b4479777 |
13 | 87a04740022b0 |
14 | 376722d2513d1 |
15 | 182589e9c5291 |
hex | b62ecc2b280b |
200312110131211 has 8 divisors (see below), whose sum is σ = 218940446435984. Its totient is φ = 182143732747680.
The previous prime is 200312110131149. The next prime is 200312110131239. The reversal of 200312110131211 is 112131011213002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 200312110131211 - 219 = 200312109606923 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200312110131611) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 114989729400 + ... + 114989731141.
It is an arithmetic number, because the mean of its divisors is an integer number (27367555804498).
Almost surely, 2200312110131211 is an apocalyptic number.
200312110131211 is a deficient number, since it is larger than the sum of its proper divisors (18628336304773).
200312110131211 is a wasteful number, since it uses less digits than its factorization.
200312110131211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 229979460621.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 200312110131211 its reverse (112131011213002), we get a palindrome (312443121344213).
The spelling of 200312110131211 in words is "two hundred trillion, three hundred twelve billion, one hundred ten million, one hundred thirty-one thousand, two hundred eleven".
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