Base | Representation |
---|---|
bin | 1001000110111111000010… |
… | …01101111010001110100111 |
3 | 2121220222001112111122211202 |
4 | 10203133201031322032213 |
5 | 10111142410010134343 |
6 | 110334113350353115 |
7 | 4135131040230563 |
oct | 443374115721647 |
9 | 77828045448752 |
10 | 20031211021223 |
11 | 6423209455256 |
12 | 22b622405b79b |
13 | b23c2052b92c |
14 | 4d37314646a3 |
15 | 24b0cee75db8 |
hex | 1237e137a3a7 |
20031211021223 has 2 divisors, whose sum is σ = 20031211021224. Its totient is φ = 20031211021222.
The previous prime is 20031211021201. The next prime is 20031211021259. The reversal of 20031211021223 is 32212011213002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20031211021223 - 238 = 19756333114279 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20031211021195 and 20031211021204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20031211021823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10015605510611 + 10015605510612.
It is an arithmetic number, because the mean of its divisors is an integer number (10015605510612).
Almost surely, 220031211021223 is an apocalyptic number.
20031211021223 is a deficient number, since it is larger than the sum of its proper divisors (1).
20031211021223 is an equidigital number, since it uses as much as digits as its factorization.
20031211021223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 20031211021223 its reverse (32212011213002), we get a palindrome (52243222234225).
The spelling of 20031211021223 in words is "twenty trillion, thirty-one billion, two hundred eleven million, twenty-one thousand, two hundred twenty-three".
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