2003121112117 has 4 divisors (see below), whose sum is σ = 2004219918720. Its totient is φ = 2002022305516.

The previous prime is 2003121112103. The next prime is 2003121112127. The reversal of 2003121112117 is 7112111213002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2003121112117 - 2⁷ = 2003121111989 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003121112127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 549400567 + ... + 549404212.

It is an arithmetic number, because the mean of its divisors is an integer number (501054979680).

Almost surely, 2^{2003121112117} is an apocalyptic number.

It is an amenable number.

2003121112117 is a deficient number, since it is larger than the sum of its proper divisors (1098806603).

2003121112117 is a wasteful number, since it uses less digits than its factorization.

2003121112117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1098806602.

The product of its (nonzero) digits is 168, while the sum is 22.

Adding to 2003121112117 its reverse (7112111213002), we get a palindrome (9115232325119).

The spelling of 2003121112117 in words is "two trillion, three billion, one hundred twenty-one million, one hundred twelve thousand, one hundred seventeen".