Base | Representation |
---|---|
bin | 11101001001100011010… |
… | …100101000010000100111 |
3 | 21002111101221202202212122 |
4 | 131021203110220100213 |
5 | 230304343001041403 |
6 | 4132115433140155 |
7 | 264502131343166 |
oct | 35114324502047 |
9 | 7074357682778 |
10 | 2003121112103 |
11 | 702578712581 |
12 | 28427525a65b |
13 | 116b80071a77 |
14 | 6cd471c13dd |
15 | 3718bee6838 |
hex | 1d263528427 |
2003121112103 has 2 divisors, whose sum is σ = 2003121112104. Its totient is φ = 2003121112102.
The previous prime is 2003121112093. The next prime is 2003121112127. The reversal of 2003121112103 is 3012111213002.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2003121112103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003121112133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001560556051 + 1001560556052.
It is an arithmetic number, because the mean of its divisors is an integer number (1001560556052).
Almost surely, 22003121112103 is an apocalyptic number.
2003121112103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003121112103 is an equidigital number, since it uses as much as digits as its factorization.
2003121112103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2003121112103 its reverse (3012111213002), we get a palindrome (5015232325105).
The spelling of 2003121112103 in words is "two trillion, three billion, one hundred twenty-one million, one hundred twelve thousand, one hundred three".
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