Base | Representation |
---|---|
bin | 11101001001100011011… |
… | …000000011111111100101 |
3 | 21002111102000110111111002 |
4 | 131021203120003333211 |
5 | 230304343213342013 |
6 | 4132115504323045 |
7 | 264502142112164 |
oct | 35114330037745 |
9 | 7074360414432 |
10 | 2003122012133 |
11 | 702579177800 |
12 | 284275613485 |
13 | 116b802c8628 |
14 | 6cd473773db |
15 | 3718c123358 |
hex | 1d263603fe5 |
2003122012133 has 6 divisors (see below), whose sum is σ = 2201778740742. Its totient is φ = 1821020010920.
The previous prime is 2003122012093. The next prime is 2003122012141. The reversal of 2003122012133 is 3312102213002.
It can be written as a sum of positive squares in only one way, i.e., 1169994845569 + 833127166564 = 1081663^2 + 912758^2 .
It is not a de Polignac number, because 2003122012133 - 218 = 2003121749989 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2003122012033) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 8277363566 + ... + 8277363807.
It is an arithmetic number, because the mean of its divisors is an integer number (366963123457).
Almost surely, 22003122012133 is an apocalyptic number.
It is an amenable number.
2003122012133 is a deficient number, since it is larger than the sum of its proper divisors (198656728609).
2003122012133 is a wasteful number, since it uses less digits than its factorization.
2003122012133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16554727395 (or 16554727384 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2003122012133 its reverse (3312102213002), we get a palindrome (5315224225135).
The spelling of 2003122012133 in words is "two trillion, three billion, one hundred twenty-two million, twelve thousand, one hundred thirty-three".
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