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2003124013232 = 24472663728741
BaseRepresentation
bin11101001001100011011…
…111101100100010110000
321002111102011020011110212
4131021203133230202300
5230304344221410412
64132120015243252
7264502165115246
oct35114337544260
97074364204425
102003124013232
1170257a314201
12284276219528
13116b80849404
146cd47738796
153718c3bb222
hex1d2637ec8b0

2003124013232 has 20 divisors (see below), whose sum is σ = 3963628368096. Its totient is φ = 980252176320.

The previous prime is 2003124013201. The next prime is 2003124013237. The reversal of 2003124013232 is 2323104213002.

It is a super-2 number, since 2×20031240132322 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2003124013198 and 2003124013207.

It is not an unprimeable number, because it can be changed into a prime (2003124013237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1331863619 + ... + 1331865122.

Almost surely, 22003124013232 is an apocalyptic number.

It is an amenable number.

2003124013232 is a deficient number, since it is larger than the sum of its proper divisors (1960504354864).

2003124013232 is a wasteful number, since it uses less digits than its factorization.

2003124013232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2663728796 (or 2663728790 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 2003124013232 its reverse (2323104213002), we get a palindrome (4326228226234).

The spelling of 2003124013232 in words is "two trillion, three billion, one hundred twenty-four million, thirteen thousand, two hundred thirty-two".

Divisors: 1 2 4 8 16 47 94 188 376 752 2663728741 5327457482 10654914964 21309829928 42619659856 125195250827 250390501654 500781003308 1001562006616 2003124013232