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200313413103 = 366771137701
BaseRepresentation
bin1011101010001110011…
…1000001110111101111
3201011001012000201110010
42322203213001313233
511240220213204403
6232004523344303
720320644626556
oct2724347016757
9634035021403
10200313413103
1177a527770a1
12329a4682093
1315b7423520b
1499a3986d9d
155325c32603
hex2ea39c1def

200313413103 has 4 divisors (see below), whose sum is σ = 267084550808. Its totient is φ = 133542275400.

The previous prime is 200313413071. The next prime is 200313413129. The reversal of 200313413103 is 301314313002.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 200313413103 - 25 = 200313413071 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200313413103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200313413603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33385568848 + ... + 33385568853.

It is an arithmetic number, because the mean of its divisors is an integer number (66771137702).

Almost surely, 2200313413103 is an apocalyptic number.

200313413103 is a deficient number, since it is larger than the sum of its proper divisors (66771137705).

200313413103 is an equidigital number, since it uses as much as digits as its factorization.

200313413103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66771137704.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 200313413103 its reverse (301314313002), we get a palindrome (501627726105).

The spelling of 200313413103 in words is "two hundred billion, three hundred thirteen million, four hundred thirteen thousand, one hundred three".

Divisors: 1 3 66771137701 200313413103