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2003140101 = 3667713367
BaseRepresentation
bin111011101100101…
…0111111000000101
312011121021001122010
41313121113320011
513100300440401
6530434124433
7100432260414
oct16731277005
95147231563
102003140101
119387a1896
1247aa20719
1325c006701
1415007547b
15bacd2ed6
hex77657e05

2003140101 has 4 divisors (see below), whose sum is σ = 2670853472. Its totient is φ = 1335426732.

The previous prime is 2003140099. The next prime is 2003140109. The reversal of 2003140101 is 1010413002.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2003140101 - 21 = 2003140099 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003140109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333856681 + ... + 333856686.

It is an arithmetic number, because the mean of its divisors is an integer number (667713368).

Almost surely, 22003140101 is an apocalyptic number.

It is an amenable number.

2003140101 is a deficient number, since it is larger than the sum of its proper divisors (667713371).

2003140101 is an equidigital number, since it uses as much as digits as its factorization.

2003140101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 667713370.

The product of its (nonzero) digits is 24, while the sum is 12.

The square root of 2003140101 is about 44756.4531771676. The cubic root of 2003140101 is about 1260.5800850004.

Adding to 2003140101 its reverse (1010413002), we get a palindrome (3013553103).

The spelling of 2003140101 in words is "two billion, three million, one hundred forty thousand, one hundred one".

Divisors: 1 3 667713367 2003140101