Base | Representation |
---|---|
bin | 101101100011000010101010… |
… | …001111111110011011000000 |
3 | 222021021102021100120211210010 |
4 | 231203002222033332123000 |
5 | 202224021112014000000 |
6 | 1550013444151504520 |
7 | 60123436406031234 |
oct | 5543025217763300 |
9 | 867242240524703 |
10 | 200320131000000 |
11 | 58912321683930 |
12 | 1a573472688140 |
13 | 87a11519710bb |
14 | 37677905cc5c4 |
15 | 1825bbdc43d50 |
hex | b630aa3fe6c0 |
200320131000000 has 392 divisors, whose sum is σ = 722736795100608. Its totient is φ = 48562448000000.
The previous prime is 200320130999977. The next prime is 200320131000007. The reversal of 200320131000000 is 131023002.
It is a happy number.
200320131000000 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×2003201310000002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a self number, because there is not a number n which added to its sum of digits gives 200320131000000.
It is not an unprimeable number, because it can be changed into a prime (200320131000007) by changing a digit.
It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 29964847 + ... + 36035153.
Almost surely, 2200320131000000 is an apocalyptic number.
200320131000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 200320131000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (361368397550304).
200320131000000 is an abundant number, since it is smaller than the sum of its proper divisors (522416664100608).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200320131000000 is an frugal number, since it uses more digits than its factorization.
200320131000000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6070363 (or 6070328 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 12.
Adding to 200320131000000 its reverse (131023002), we get a palindrome (200320262023002).
The spelling of 200320131000000 in words is "two hundred trillion, three hundred twenty billion, one hundred thirty-one million", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •