Base | Representation |
---|---|
bin | 10010101010000000… |
… | …001010110001110011 |
3 | 1220201001211001221022 |
4 | 102222000022301303 |
5 | 312011200240201 |
6 | 13111432050055 |
7 | 1306261350062 |
oct | 225200126163 |
9 | 56631731838 |
10 | 20032040051 |
11 | 854a623201 |
12 | 3a7083392b |
13 | 1b7321534a |
14 | d806661d9 |
15 | 7c399941b |
hex | 4aa00ac73 |
20032040051 has 2 divisors, whose sum is σ = 20032040052. Its totient is φ = 20032040050.
The previous prime is 20032040023. The next prime is 20032040053. The reversal of 20032040051 is 15004023002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20032040051 is a prime.
Together with 20032040053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20032040053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10016020025 + 10016020026.
It is an arithmetic number, because the mean of its divisors is an integer number (10016020026).
Almost surely, 220032040051 is an apocalyptic number.
20032040051 is a deficient number, since it is larger than the sum of its proper divisors (1).
20032040051 is an equidigital number, since it uses as much as digits as its factorization.
20032040051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 17.
Adding to 20032040051 its reverse (15004023002), we get a palindrome (35036063053).
The spelling of 20032040051 in words is "twenty billion, thirty-two million, forty thousand, fifty-one".
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