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200321000111 is a prime number
BaseRepresentation
bin1011101010010000001…
…1111110001010101111
3201011001201022011212102
42322210003332022233
511240224134000421
6232005354125315
720321066256251
oct2724403761257
9634051264772
10200321000111
1177a56a89351
12329a712083b
1315b7599067b
1499a499dcd1
15532673060b
hex2ea40fe2af

200321000111 has 2 divisors, whose sum is σ = 200321000112. Its totient is φ = 200321000110.

The previous prime is 200321000027. The next prime is 200321000129. The reversal of 200321000111 is 111000123002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 200321000111 - 222 = 200316805807 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200321000092 and 200321000101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200321000171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100160500055 + 100160500056.

It is an arithmetic number, because the mean of its divisors is an integer number (100160500056).

Almost surely, 2200321000111 is an apocalyptic number.

200321000111 is a deficient number, since it is larger than the sum of its proper divisors (1).

200321000111 is an equidigital number, since it uses as much as digits as its factorization.

200321000111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 200321000111 its reverse (111000123002), we get a palindrome (311321123113).

The spelling of 200321000111 in words is "two hundred billion, three hundred twenty-one million, one hundred eleven", and thus it is an aban number.