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200321000141 = 250338002277
BaseRepresentation
bin1011101010010000001…
…1111110001011001101
3201011001201022011220112
42322210003332023031
511240224134001031
6232005354125405
720321066256323
oct2724403761315
9634051264815
10200321000141
1177a56a89379
12329a7120865
1315b759906a2
1499a499dd13
15532673062b
hex2ea40fe2cd

200321000141 has 4 divisors (see below), whose sum is σ = 200329027452. Its totient is φ = 200312972832.

The previous prime is 200321000129. The next prime is 200321000147. The reversal of 200321000141 is 141000123002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 25425578116 + 174895422025 = 159454^2 + 418205^2 .

It is a cyclic number.

It is not a de Polignac number, because 200321000141 - 222 = 200316805837 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200321000147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3976106 + ... + 4026171.

It is an arithmetic number, because the mean of its divisors is an integer number (50082256863).

Almost surely, 2200321000141 is an apocalyptic number.

It is an amenable number.

200321000141 is a deficient number, since it is larger than the sum of its proper divisors (8027311).

200321000141 is an equidigital number, since it uses as much as digits as its factorization.

200321000141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8027310.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 200321000141 its reverse (141000123002), we get a palindrome (341321123143).

The spelling of 200321000141 in words is "two hundred billion, three hundred twenty-one million, one hundred forty-one", and thus it is an aban number.

Divisors: 1 25033 8002277 200321000141