Base | Representation |
---|---|
bin | 101101100011000101011101… |
… | …101011110010110110100111 |
3 | 222021021201001011012201212110 |
4 | 231203011131223302312213 |
5 | 202224043243200224221 |
6 | 1550015103011252103 |
7 | 60123604122110316 |
oct | 5543053553626647 |
9 | 867251034181773 |
10 | 200323141414311 |
11 | 58913626a07743 |
12 | 1a573b728aa033 |
13 | 87a1511560946 |
14 | 376799834627d |
15 | 1825ce8193776 |
hex | b6315daf2da7 |
200323141414311 has 4 divisors (see below), whose sum is σ = 267097521885752. Its totient is φ = 133548760942872.
The previous prime is 200323141414307. The next prime is 200323141414313. The reversal of 200323141414311 is 113414141323002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 200323141414311 - 22 = 200323141414307 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200323141414313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33387190235716 + ... + 33387190235721.
It is an arithmetic number, because the mean of its divisors is an integer number (66774380471438).
Almost surely, 2200323141414311 is an apocalyptic number.
200323141414311 is a deficient number, since it is larger than the sum of its proper divisors (66774380471441).
200323141414311 is an equidigital number, since it uses as much as digits as its factorization.
200323141414311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66774380471440.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 200323141414311 its reverse (113414141323002), we get a palindrome (313737282737313).
The spelling of 200323141414311 in words is "two hundred trillion, three hundred twenty-three billion, one hundred forty-one million, four hundred fourteen thousand, three hundred eleven".
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