Base | Representation |
---|---|
bin | 11101001001101110101… |
… | …001110000101110111011 |
3 | 21002111220012110022002222 |
4 | 131021232221300232323 |
5 | 230310240131414321 |
6 | 4132150343314255 |
7 | 264506630151635 |
oct | 35115651605673 |
9 | 7074805408088 |
10 | 2003311201211 |
11 | 702665a46311 |
12 | 284308a4b98b |
13 | 116bb0568c28 |
14 | 6cd64543a55 |
15 | 3719da443ab |
hex | 1d26ea70bbb |
2003311201211 has 4 divisors (see below), whose sum is σ = 2003318922192. Its totient is φ = 2003303480232.
The previous prime is 2003311201189. The next prime is 2003311201219. The reversal of 2003311201211 is 1121021133002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2003311201211 - 218 = 2003310939067 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2003311201211.
It is not an unprimeable number, because it can be changed into a prime (2003311201219) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3457256 + ... + 3994901.
It is an arithmetic number, because the mean of its divisors is an integer number (500829730548).
Almost surely, 22003311201211 is an apocalyptic number.
2003311201211 is a deficient number, since it is larger than the sum of its proper divisors (7720981).
2003311201211 is an equidigital number, since it uses as much as digits as its factorization.
2003311201211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7720980.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2003311201211 its reverse (1121021133002), we get a palindrome (3124332334213).
The spelling of 2003311201211 in words is "two trillion, three billion, three hundred eleven million, two hundred one thousand, two hundred eleven".
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