20033131414433 has 4 divisors (see below), whose sum is σ = 20904137128128. Its totient is φ = 19162125700740.

The previous prime is 20033131414367. The next prime is 20033131414459. The reversal of 20033131414433 is 33441413133002.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20033131414433 - 2¹⁰ = 20033131413409 is a prime.

It is a super-2 number, since 2×20033131414433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20033131414433.

It is not an unprimeable number, because it can be changed into a prime (20033131414633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435502856813 + ... + 435502856858.

It is an arithmetic number, because the mean of its divisors is an integer number (5226034282032).

Almost surely, 2^{20033131414433} is an apocalyptic number.

20033131414433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

20033131414433 is a deficient number, since it is larger than the sum of its proper divisors (871005713695).

20033131414433 is an equidigital number, since it uses as much as digits as its factorization.

20033131414433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 871005713694.

The product of its (nonzero) digits is 31104, while the sum is 32.

Adding to 20033131414433 its reverse (33441413133002), we get a palindrome (53474544547435).

The spelling of 20033131414433 in words is "twenty trillion, thirty-three billion, one hundred thirty-one million, four hundred fourteen thousand, four hundred thirty-three".