Base | Representation |
---|---|
bin | 101101100011001101101110… |
… | …010010110000111011111010 |
3 | 222021022112221020000120111121 |
4 | 231203031232102300323322 |
5 | 202224214424030000442 |
6 | 1550023131020015454 |
7 | 60124336650620530 |
oct | 5543155622607372 |
9 | 867275836016447 |
10 | 200332010000122 |
11 | 58917368000500 |
12 | 1a57582899158a |
13 | 87a22c5a1b860 |
14 | 376819a110150 |
15 | 1826166a62967 |
hex | b6336e4b0efa |
200332010000122 has 96 divisors (see below), whose sum is σ = 406772358765696. Its totient is φ = 72003180839040.
The previous prime is 200332010000119. The next prime is 200332010000159. The reversal of 200332010000122 is 221000010233002.
It is a junction number, because it is equal to n+sod(n) for n = 200332010000096 and 200332010000105.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 33034188 + ... + 38625400.
It is an arithmetic number, because the mean of its divisors is an integer number (4237212070476).
Almost surely, 2200332010000122 is an apocalyptic number.
200332010000122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
200332010000122 is an abundant number, since it is smaller than the sum of its proper divisors (206440348765574).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200332010000122 is a wasteful number, since it uses less digits than its factorization.
200332010000122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5592884 (or 5592873 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 200332010000122 its reverse (221000010233002), we get a palindrome (421332020233124).
The spelling of 200332010000122 in words is "two hundred trillion, three hundred thirty-two billion, ten million, one hundred twenty-two", and thus it is an aban number.
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