Base | Representation |
---|---|
bin | 101101100011001101101110… |
… | …011010111001101011101100 |
3 | 222021022112221101000221101210 |
4 | 231203031232122321223230 |
5 | 202224214430101224400 |
6 | 1550023131133434420 |
7 | 60124340005013241 |
oct | 5543155632715354 |
9 | 867275841027353 |
10 | 200332012133100 |
11 | 58917369227aa1 |
12 | 1a57582963ba10 |
13 | 87a22c62b7683 |
14 | 376819a5075c8 |
15 | 1826166d34950 |
hex | b6336e6b9aec |
200332012133100 has 144 divisors (see below), whose sum is σ = 595309598247168. Its totient is φ = 51976576776960.
The previous prime is 200332012133087. The next prime is 200332012133131. The reversal of 200332012133100 is 1331210233002.
It is a super-2 number, since 2×2003320121331002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 427859719 + ... + 428327681.
It is an arithmetic number, because the mean of its divisors is an integer number (4134094432272).
Almost surely, 2200332012133100 is an apocalyptic number.
200332012133100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
200332012133100 is an abundant number, since it is smaller than the sum of its proper divisors (394977586114068).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200332012133100 is a wasteful number, since it uses less digits than its factorization.
200332012133100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 506584 (or 506577 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 200332012133100 its reverse (1331210233002), we get a palindrome (201663222366102).
The spelling of 200332012133100 in words is "two hundred trillion, three hundred thirty-two billion, twelve million, one hundred thirty-three thousand, one hundred".
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