Base | Representation |
---|---|
bin | 1011101010010011011… |
… | …0101111111100111111 |
3 | 201011002122100110021212 |
4 | 2322210312233330333 |
5 | 11240241040424411 |
6 | 232010551315035 |
7 | 20321320356215 |
oct | 2724466577477 |
9 | 634078313255 |
10 | 200334311231 |
11 | 77a6355017a |
12 | 329ab67ba7b |
13 | 15b78671382 |
14 | 99a6666cb5 |
15 | 53279ae68b |
hex | 2ea4daff3f |
200334311231 has 2 divisors, whose sum is σ = 200334311232. Its totient is φ = 200334311230.
The previous prime is 200334311201. The next prime is 200334311237. The reversal of 200334311231 is 132113433002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200334311231 - 210 = 200334310207 is a prime.
It is a super-3 number, since 3×2003343112313 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 200334311197 and 200334311206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200334311237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100167155615 + 100167155616.
It is an arithmetic number, because the mean of its divisors is an integer number (100167155616).
Almost surely, 2200334311231 is an apocalyptic number.
200334311231 is a deficient number, since it is larger than the sum of its proper divisors (1).
200334311231 is an equidigital number, since it uses as much as digits as its factorization.
200334311231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 200334311231 its reverse (132113433002), we get a palindrome (332447744233).
The spelling of 200334311231 in words is "two hundred billion, three hundred thirty-four million, three hundred eleven thousand, two hundred thirty-one".
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